Question

A 675-pound trailer is sitting on an exit ramp inclined at 40o on Highway 35. How much vertical force is required to keep the trailer from rolling back down the exit ramp?

Answer 1

433.88 lbs

Step-by-step explanation:

We are given that mass of trailer =675 pound

Angle=
`40^(\circ)`

We have to find the vertical force required to keep the trailer from rolling back down the exit ramp.

The force required to keep the trailer from rolling back down the exit ramp=
`wsin\theta`

Where w=675 pounds and
`\theta=40^(\circ)`

Substitute the values then we get

`F=675 sin40^(\circ)`

`sin40^(\circ)=0.642787`

Substitute the value then we get

`F=675* 0.642787`=433.88 lbs

Hence, the force required to keep the trailer from rolling back down the exits ramp=433.88 lbs