Question

A sample of neon is collected at 2.7 atm and 12.0 oC. It has a volume of 2.25 L. What would be the volume of this gas at STP?

Answer 1

5.82 L

Step-by-step explanation:

Using Ideal gas equation for same mole of gas as

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

Given ,

V₁ = 2.25 L

V₂ = ?

P₁ = 2.7 atm

T₁ = 12 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (12 + 273.15) K = 285.15 K

At STP, Pressure = 1 atm and Temperature = 273.15 K

So,

P₂ = 1 atm

T₂ = 273.15 K

Using above equation as:

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

`\frac {{2.7}* {2.25}}{285.15}=\frac {{1}* {V_2}}{273.15}`

Solving for V₂ , we get:

V₂ = 5.82 L