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Two molecules, A and B, have very different physical properties. A and B do not mix. Molecule A boils at 82 C and freezes at 0 C. Molecule B boils at 38 C and freezes at -68 C. Which molecule has the higher total intermolecular forces?

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Final answer:

Molecule A has higher total intermolecular forces compared to molecule B due to its higher boiling and freezing points.

Step-by-step explanation:

Boiling points and freezing points of molecules are determined by the intermolecular forces between molecules. Molecule A has a boiling point of 82°C and freezing point of 0°C, while molecule B has a boiling point of 38°C and freezing point of -68°C. The higher total intermolecular forces are observed in molecule A because it has a higher boiling point and freezing point compared to molecule B. These differences in physical properties indicate that molecule A has stronger intermolecular forces.

User Punita
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3 votes

Answer:

Molecule A

Step-by-step explanation:

Molecules with the stronger intermolecular forces are pulled tightly together to form solid at higher temperatures and that's why the freezing point is higher.

Also, molecules with the stronger intermolecular force have greater interaction between the molecules and thus on heating do not boil easily and have high boiling point also.

So, Molecule A has boiling point and melting point both greater than molecule A . So, it has the higher total intermolecular forces.

User Fojeeck
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4.9k points