Answer:
![98√(6)\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/w53snaabp6ozbv1kapg5dgw64ixljn3d2s.png)
Explanation:
The complete question is
A builder needs three pipes of different lengths. The pipes are 6√96 feet long, 12√150 feet long, and 2√294 feet long. How many feet of piping is required in all?
we know that
![6√(96)\ ft=6√(16(6)) =6\sqrt{4^(2)(6)}=6(4)√(6) =24√(6)\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/p0ow4c6gq8unlle35jia6p6z3ighdyofh0.png)
![12√(150)\ ft=12√(25(6)) =12\sqrt{5^(2)(6)}=12(5)√(6) =60√(6)\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/i7m92v857yku99fkvdjcw0oi6bsjxwkitg.png)
![2√(294)\ ft=2√(49(6)) =2\sqrt{7^(2)(6)}=2(7)√(6) =14√(6)\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/iitxn1hsisy0otg51diu1jxx23h1s1gqko.png)
Sum the length of the three pipes
![24√(6)+60√(6)+14√(6)=98√(6)\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/zjmuo7sca6j7lmt4cld8w8i3je92omua82.png)