Question

Aluminum reacts with excess copper(II) sul- fate according to the unbalanced reaction Al(s) + CuSO4(aq) −→ Al2(SO4)3(aq) + Cu(s) If 1.37 g of Al react and the percent yield of Cu is 67.4%, what mass of Cu is produced? Answer in units of g.

Answer 1

To find the mass of Cu produced, we first determine the theoretical yield based on the given mass of Al. Then, we calculate the actual yield using the percent yield. The mass of Cu produced is 2.17 g.

Step-by-step explanation:

To find the mass of Cu produced, we first need to determine the theoretical yield of Cu using the balanced equation and the given mass of Al. The molar ratio between Al and Cu is 1:1, so the number of moles of Cu produced is equal to the number of moles of Al. The molar mass of Cu is 63.55 g/mol. Therefore, the theoretical yield of Cu is 1.37 g * (1 mol Cu / 26.98 g Al) = 0.0507 mol Cu.

Next, we can calculate the actual yield of Cu by multiplying the percent yield (67.4%) by the theoretical yield. Actual yield = 0.674 * 0.0507 mol = 0.0341 mol.

Finally, we can convert the actual yield from moles to grams by multiplying by the molar mass of Cu: 0.0341 mol * 63.55 g/mol = 2.17 g Cu.

Answer 2

2.09 g Cu

Step-by-step explanation:

First, we have to balance the equation:

3Al(s) + 3CuSO4(aq) = Al2(SO4)3(aq) + 3Cu(s)

Then we have to change grams of Al to mol:

1 mol Al = 26.98 g

1.37 g Al x (1 mol/26.98 g) = 0.051 mol

Then, we use the balanced equation to find the mol of Cu produced:

According to the equation:

3 mol Al produces 3 mol of Cu

3 mol Al = 3 mol Cu

So:

0.051 mol Al x (3 mol Cu/3 mol Al) = 0.051 mol Cu

This mol value is the theoric yield of the reaction.

Remember the equation for yield percent:

%Y = (Y real / Y theoric) x 100

Y theoric = 0.051 mol Cu

% Y = 67.4%

Let's replace these values on the equation and then fin Y real.

67.4 % = (Y real / 0.051) x 100

Y real = 0.033 mol Cu

So the real produced mol is 0.033 mol Cu.

Let's change these moles to grams:

1 mol Cu = 63.55 g

0.033 mol Cu x ( 63.55 g Cu/ 1 mol Cu) = 2.09 g Cu

If you want, watch the image attached is more clear the

mathematical procedure