Answer:
0.25
Explanation:
Given that a recently married couple are planning to have four children. They are equally likely to have a boy as well as a girl.
Let X be the no of boys the couples have. X has two outcomes with p = 0.5
X is binomial with n = no of trials = 4 and p =0.5
the probability that they will have three boys and one girl
=
![P(X=3)\\=4C3(0.5)^3(0.5)\\= 0.25](https://img.qammunity.org/2020/formulas/mathematics/high-school/2jakz5gd8sqd5a68yywqhl6gqsbyhe3b4v.png)
Reqd prob = 0.25