Question

One of the dangers of tornados and hurricanes is the rapid drop in air pressurethat is associated with such storms. Assume that the air pressure inside of a sealed houseis 1.02 atm when a hurricane hits. The hurricane rapidly decreases the external airpressure to 0.910 atm. What net outward force is exerted on a square window of thehouse that is 2.03 m on each side

Answer 1

The net outward force is exerted on a square window of the house is
`4.5930*10^(4)\ N`.

Step-by-step explanation:

Given that,

Pressure = 1.02 atm

External air pressure = 0.910 atm

Distance = 2.03 m

We need to calculate the net outward force

Using formula of force

`F= PA`

Where, P = pressure

F = force

A = area

Put the value into the formula

`F=(1.02-0.910)*101325*(2.03)^2`

`F=4.5930*10^(4)\ N`

Hence, The net outward force is exerted on a square window of the house is
`4.5930*10^(4)\ N`.