Question

An AC circuit with a total resistance of R has an rms current of I. The circuit wraps around an iron core transistor with 50 loops. The secondary coils, leading to a different circuit, wrap with N loops. The secondary circuit has a total resistance of 40 Ω. What is the rms current in the secondary circuit (6 points)?Assigned values for 15.0 Ω R = , I = 5.0 amp, and N = 18

Answer 1

current is 13.88 A

Step-by-step explanation:

given data

no of loops = 50 loops

resistance = 40 Ω

R = 15.0 Ω

I = 5.0 amp

N = 18

to find out

rms current

solution

we will apply here transformed principle that is

v(s) / v(p) = I(p) / I(s) = N(s) / N(p) ....................1

here p is primary and s is secondary

put here all these value

5 / I(s) = 18 / 50

I(s) = 250 /18

I(s) = 13.88

so current is 13.88 A