Question

A baby sitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.747 m/s2 . What is the velocity of the stroller after it has traveled 6.87 m? Answer in units of m/s.

Answer 1

The velocity of the stroller is 3.204 m/s.

Step-by-step explanation:

Given that,

Distance = 6.87 m

Acceleration = 0.747 m/s²

We need to calculate the velocity

Using equation of motion

`v^2=u^2+2as`

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value into the formula

`v^2=0+2*0.747*6.87`

`v^(2)=10.26378`

`v=√(10.26378)`

`v=3.204\ m/s`

Hence, The velocity of the stroller is 3.204 m/s.

Answer 2

3.2037 m/sec

Step-by-step explanation:

We have given initial velocity u =0 m/sec

Acceleration
`a=0.747m/sec^2`

Distance traveled
`s=6.87 m`

We have to find the final velocity v

According to third law of motion
`v^2=u^2+2as`

`v^2=u^2+2as=0^2+2* 0.747* 6.87=10.2637`

`v=3.2037m/sec`

So the final velocity is 3.2037 m/sec