Answers:
a)
![T=7.04(10)^(-10) s](https://img.qammunity.org/2020/formulas/physics/high-school/a8752e2loykfpk4c0nemyeyzc5gtlgru48.png)
b)
![5.11(10)^(12) cycles](https://img.qammunity.org/2020/formulas/physics/high-school/w6utlm80qa36snepuc87wr1bq5i4zfpaxf.png)
c)
![2.06(10)^(26) cycles](https://img.qammunity.org/2020/formulas/physics/high-school/51v168h36rkmtnnsx2kyywjvhxbwa6yp5g.png)
d) 46000 s
Step-by-step explanation:
a) Time for one cycle of the radio wave
We know the maser radiowave has a frequency
of
![1,420,405,751.786 cycles/s](https://img.qammunity.org/2020/formulas/physics/high-school/tulbirrcu86sav861z2axbtej6hyocdqfe.png)
In addition we know there is an inverse relation between frequency and time
:
(1)
Isolating
:
(2)
(3)
(4) This is the time for 1 cycle
b) Cycles that occur in 1 h
If
and we already know the amount of cycles per second
, then:
This is the number of cycles in an hour
c) How many cycles would have occurred during the age of the earth, which is estimated to be
?
Firstly, we have to convert this from years to seconds:
![4.6(10)^(9) years (365 days)/(1 year) (24 h)/(1 day) (3600 s)/(1 h)=1.45(10)^(17) s](https://img.qammunity.org/2020/formulas/physics/high-school/u2x7x1rxvrz2s6uvfyziyn350bkye9ga35.png)
Now we have to multiply this value for the frequency of the maser radiowave:
This is the number of cycles in the age of the Earth
d) By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth?
If we have 1 second out for every 100,000 years, then:
![4.6(10)^(9) years (1 s)/(100,000 years)=46000 s](https://img.qammunity.org/2020/formulas/physics/high-school/9oar9sjk6obg8rjb4vypz1uxd6gpm6bcqz.png)
This means the maser would be 46000 s off after a time interval equal to the age of the earth