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A 100-turn, 3.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 60%u2218 away from vertical increases from 0.50 T to 2.5T in 0.90s .

What is the induced emf in the coil?

User Graeme
by
7.8k points

1 Answer

3 votes

Answer:

Induced emf in the coil, E = 0.157 volts

Step-by-step explanation:

It is given that,

Number of turns, N = 100

Diameter of the coil, d = 3 cm = 0.03 m

Radius of the coil, r = 0.015 m

A uniform magnetic field increases from 0.5 T to 2.5 T in 0.9 s.

Due to this change in magnetic field, an emf is induced in the coil which is given by :


E=-NA(\Delta B)/(\Delta t)


E=-100* \pi (0.015)^2* (2.5-0.5)/(0.9)

E = -0.157 volts

Minus sign shows the direction of induced emf in the coil. Hence, the induced emf in the coil is 0.157 volts.

User Marsman
by
7.5k points
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