Question

A 12-kg hammer strikes a nail at a velocity of 8.5 m/s and comes to rest in a time interval of 8.0 ms. (A) What is the impulse given to the nail? (Write the unit for impulse as a kg.m/s or as N.s)

Answer 1

The impulse is 102 kg m/s.

Step-by-step explanation:

Given that,

Mass of hammer = 12 kg

Velocity = 8.5 m/s

Time = 8.0 ms

Impulse :

Impulse is the change in momentum of the object.

We need to calculate the impulse

Using formula of impulse

`\Delta p=p_(f)-p_(i)`

`\Delta p=m(v-u)`

Where, m = mass of the object

v = final velocity

u = initial velocity

Put the value into the formula

`\Delta p=12*(8.5-0)`

`\Delta p=102\ Kg.m/s`

Hence, The impulse is 102 kg m/s.

Answer 2

102 kg.m/s

Step-by-step explanation:

m = Mass of hammer = 12 kg

v = Final velocity = 8.5 m/s

u = Initial velocity = 0

t = Time taken = 8 ms

Force acting over a given amount of time or change in momentum is known as impulse.

Impulse

`J=Ft\\\Rightarrow J=p_2-p_1\\\Rightarrow J=m(v-u)\\\Rightarrow J=12(8.5-0)\\\Rightarrow J=102\kg.m/s`

Impulse given to the nail is 102 kg.m/s