Answer:
5
Explanation:
(h + k)(x) = [(x^2 + 1) + (x - 2)]
=[ x^2 + x -1 ]
then for [(h + k)(2)]....substitute x with 2 and then calculate...,
; (2)^2 + 2 - 1
; 4 + 2 - 1
(h + k)(2) = 5
(h + k)(x) = x - 2 + 2x + 1
(h + k)(x) = 3x - 1
(h + k)(2) = 3(2) - 1
(h + k)(2) = 6 - 1
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