Step-by-step explanation:
In order to compute correctly the sum of the two terms, we have to rewrite one of them such that they have the same exponent.
The two terms are:
![8.0 \cdot 10^(-2)](https://img.qammunity.org/2020/formulas/physics/middle-school/qbpc4sowfcqby887b5ajy62m8f62ugt7if.png)
![6.0 \cdot 10^(-3)](https://img.qammunity.org/2020/formulas/physics/middle-school/17lu9wc4s28p2wuxn83js7we5fgqio5tnc.png)
For instance, we can re-write the second term such as it also has a power
. In order to do that, we have to move the decimal point one place to the left, therefore:
![6.0 \cdot 10^(-3) = 0.6\cdot 10^(-2)](https://img.qammunity.org/2020/formulas/physics/middle-school/4lrgpej7gwza7m08l3dg0qm7yvd8dl6gex.png)
At this point, the two numbers have the same exponent, so we can just add them together by adding the bases and keeping the same exponent, -2:
![8.0\cdot 10^(-2) + 0.6 \cdot 10^(-2) = (8.0 + 0.6) \cdot 10^(-2) = 8.6\cdot 10^(-2)](https://img.qammunity.org/2020/formulas/physics/middle-school/7idtdlx4spdbpa3adlgiy5g03883uwva6y.png)