Question

A person measures his or her heart rate by counting the number of beats in 30s. If 40±1 beats are counted in 30.0±0.5s, what is the heart rate and its uncertainty in beats per minute?

Answer 1

`Rate = 1.33 \pm 0.055` beats per second

Step-by-step explanation:

Number of heart beats =
`40 \pm 1`

time taken =
`30.0 \pm 0.5 s`

now we have

`N = 40 \pm 2.5`%

`t = 30.0 \pm 1.67`%

now rate of heart beat is defined as number of heart beat per unit of time

so we have

`Rate = (N)/(t)`

`Rate = (40 \pm 2.5)/(30 \pm 1.67)`

so we have

`Rate = 1.33 \pm (2.5 + 1.67 )`

`Rate = 1.33 \pm 4.17`%

`Rate = 1.33 \pm 0.055` beats per second