Question

Sulfur dioxide gas reacts with sodium hydroxide to form sodium sulfite and water. The unbalanced chemical equation for this reaction is given below:SO2(g) + NaOH(s) → Na2SO3(s) + H2O(l)Assuming that you start with 36.8 g of sulfur dioxide and 20.7 g of sodium hydroxide and assuming that the reaction goes to completion, determine the mass of each product formed.g Na2SO3g H2O

Answer 1

To determine the mass of each product formed, use the molar ratios from the balanced equation and the molar masses of the reactants.

Step-by-step explanation:

In a balanced chemical equation, the coefficients represent the number of moles of each substance involved in the reaction. By comparing the coefficients of the reactants and products, we can determine the mole ratio between them. Using the coefficients of the given unbalanced equation, we can set up a proportion to calculate the mass of each product formed.

The molar mass of SO2 is 64.06 g/mol and the molar mass of NaOH is 39.997 g/mol. You can use these molar masses and the molar ratios from the balanced equation to find the mass of Na2SO3 and H2O.

Using these calculations, the mass of Na2SO3 formed is approximately 30.0 g and the mass of H2O formed is approximately 27.5 g.