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A ball is tossed vertically upwards with a speed of 5.0 m s–1. After how many seconds will the ball return to its initial position?

User BragDeal
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1 Answer

1 vote

Answer:

1.02 seconds

Step-by-step explanation:

Initial velocity = u = 5 m/s

t = Time taken

s = Displacement travelled = 0

a = Acceleration due to gravity = -9.81 m/s² (negative sign due to direction)

Equation of motion


s=ut+(1)/(2)at^2\\\Rightarrow 0=5t+(1)/(2)-9.81* t^2\\\Rightarrow 0=5t-4.905t^2\\\Rightarrow 0=t(5-4.905t)\\\Rightarro 0=5-4.905t\\\Rightarrow t=(-5)/(-4.905)=1.02\ seconds

So, time taken to return to its initial position is 1.02 seconds

User Arasuvel
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