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Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come before $x$ or $\frac{1}{x}$.)

User Rbatt
by
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1 Answer

3 votes

Answer:


x^6+3x^3+3+(1)/(x^3)

Explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that


(x^2 + (1)/(x))^3=(x^2)^3+3(x^2)^2(1)/(x)+3x^2((1)/(x))^2+((1)/(x))^3\\\\=x^6+3x^4(1)/(x)+3x^2(1)/(x^2)+(1)/(x^3)\\\\=x^6+3x^3+3+(1)/(x^3)

User Narcy
by
5.1k points
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