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The ages of 3 brothers are represented by consecutive integers. If the oldest brother's age is decreased by twice the younger brother's age, the result is ___________.

1 Answer

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Answer:

-x+3 is the result

Explanation:

Given that the ages of 3 brothers are represented by consecutive integers. Let the ages of 3 brothers be x-1, x and x+1 in ascending order.

Oldest brother's age
= x+1

Twice the younger brother's age =
2(x-1) = 2x-2

When the above is decreased by twice younger brother age we get


x+1-(2x-2) = x+1-2x+2\\=-x+3

Result is -x+3

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