Question

The concentration of carbon monoxide in an urban apartment is 48 μg/m3. What mass of carbon monoxide in grams is present in a room measuring 12.0 × 13.5 × 22.5 ft?Express your answer using two significant figures.

Answer 1

c = 48μg/m³ = 48 * 10⁻⁶ g/m³ = 4.8 * 10⁻⁵ g/m³

1 ft = 0.3048 m

V = 12.0 * 0.3048 m * 13.5 * 0.3048 m * 22.5 * 0.3048 m = 0.3048 (12.0 + 13.5 + 22.5) m = 14.6304 m³

m = c * V

m = 4.8 * 10⁻⁵ g/m³ * 14.6304 m³ = 70,22592 * 10⁻⁵ g ≈ 70 g

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