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Factor completely 4а^2 - 8а - 5

User Paranoid
by
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1 Answer

5 votes

Answer:

(2a + 1)(2a - 5)

Explanation:

Given

4a² - 8a - 5

Consider the factors of the product of the coefficient of the a² term and the constant term which sum to give the coefficient of the a- term

product = 4 × - 5 = - 20 and sum = - 8

The factors are + 2 and - 10

Use these factors to split the a- term

4a² + 2a - 10a - 5 ( factor the first/second and third/fourth terms )

= 2a(2a + 1) - 5(2a + 1) ← factor out (2a + 1) from each term

= (2a + 1)(2a - 5)

User BSavaliya
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