Answer:
f(n)=3+(n-1)·5
Explanation:
The first term of the sequence is 3, hence
f(1)=3.
To find the second term of the the sequence we have to add 5 to f(1), hence
f(2)=3+5.
To find the third term of the sequence we have to add 5 to f(2), hence
f(3)=3+5+5 =3+2·5.
To find the fourth term of the sequence we have to add 5 to f(3), hence
f(3)=3+2·5+5=3+3·5.
To find the fifth term of the sequence we have to add 5 to f(4), hence
f(3)=3+3·5+5=3+4·5
...
and so recursively, we have that f(n)=3+(n-1)·5.