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23 votes
23 votes
Solve 9^x + 4 = 11 for x using the change of base formula log_b y= log y/ log b

User Jeebface
by
2.7k points

2 Answers

15 votes
15 votes

Answer:

Answer with explanation:

The equation is

5 X-2 = 8

Adding 2 on both sides

+5 X-2+2=8+2

+5 x=10

Dividing both sides by,5, we get

+x=2

Using the concept of Logarithms

log b

1. log, b =

=

log a

2. log ab = log a + log b

a

+ log10 5x = log10 10

=

+ log10 5 + log10 X = 1

0.698 + log10 x = 1

log10 X = 1 – 0.698

log x

=

0.302

log 10

log x = (log 100.302)

log 2

=

log 2.044

X =

2.004472

Gives, x=2.005 (Approx

Explanation:

User Netaholic
by
2.7k points
13 votes
13 votes

Answer:

Answer with explanation:

The equation is

5 X-2 = 8

Adding 2 on both sides

+5 X-2+2=8+2

+5 x=10

Dividing both sides by,5, we get

+x=2

Using the concept of Logarithms

log b

1. log, b =

=

log a

2. log ab = log a + log b

a

+ log10 5x = log10 10

=

+ log10 5 + log10 X = 1

0.698 + log10 x = 1

log10 X = 1 – 0.698

log x

=

0.302

log 10

log x = (log 100.302)

log 2

=

log 2.044

X =

2.004472

Gives, x=2.005 (Approx

User Steve Pettifer
by
2.7k points