106k views
2 votes
Evaluate -5x^2+4y^3 when x=2 and y=-2

2 Answers

7 votes

Answer:

-52

Explanation:

First plug in the values for the variables.

-5(2)^2 + 4(-2)^3

Next simplify with PEMDAS

-5(2)^2 + 4(-2)^3

-5(4) + 4(-8)

-20 + (-32)

-52

User Hilmi
by
5.2k points
3 votes

Answer:

-412 is the answer

Explanation:

(5x×5x)+(4y×4y×4y)

(25×x×x )+ (64×y×y×y)

where x=2 and y=-2

(25×2×2) +(64×-2×-2×-2)

(25×4)+(64×-8)

100+(-512)

100-512

=-412

User Harjatin
by
5.0k points
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