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Determine the mass of zinc oxide produced when 11.27g of zinc sulfide is combined with 6.97 g of oxygen. show your work.

User Emmett Butler
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1 Answer

18 votes
18 votes

2ZnS + 3O2 → 2ZnO + 2SO2

Find the limiting reagant :

n ZnS = m ZnS / Mr ZnS

n ZnS = 11.27 / 97

n ZnS = 0.116 mole

n O2 = m O2 / Mr O2

n O2 = 6.97 / 32

n O2 = 0.218 mole

n O2 / coef. O2 > n ZnS / coef. ZnS

So ZnS is the limiting reagant

Calculate the product :

n ZnO = (coef. ZnO / coef. ZnS) • n ZnS

n ZnO = 2/2 . 0.116

n ZnO = 0.116 mole

m ZnO = n ZnO • Mr ZnO

m ZnO = 0.116 • 81

m ZnO = 9.396 gr

User DrXCheng
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