68.3k views
3 votes
30 POINTS!!!!

The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1).


Find the midpoint of GH.


(1, -2)


(-4, 0)


(0, 4)


(5, 2)

User Bobwise
by
5.1k points

2 Answers

5 votes

Answer:

the third option ( 0,4)

Explanation:

Simply use the equation

(x1 + x2 ) / 2 and (y1+y2) /2

label the coordinates that join the line GH as x1, y1 , x2 and y2 respectively.

x1 = -3 y1 = 3

x2 = 3 y2 = 5

(-3 + 3) /2 and (3+5) /2

0 and 4

(0,4)

hope this answers your question

User Bui Anh Tuan
by
5.8k points
4 votes


\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ G(\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})\qquad H(\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{3-3}{2}~~,~~\cfrac{5+3}{2} \right)\implies \left(\cfrac{0}{2}~,~\cfrac{8}{2} \right)\implies (0~,~4)

User Dirk Mahler
by
5.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.