Question

Solve for the distance given the speed and time. S = 200 kph, T = 11 hours, D = ?​

Answer 1

2200

Explanation:

`S=(D)/(T) \\ \\ 200=(D)/(11) \\ \\ D=2200`

Answer 2

`\large \underline { \mathbb{ \blue{ \: \: \: DISTANCE \: \: \: }}} :`

`=======================`

`{\underline{\huge \mathbb{A} {\large \mathrm {NSWER : }}}} \\`

`\begin{gathered}\begin{gathered} \large \quad \qquad \boxed { \bold{ \: \: \: \green{Distance \: = \: 2200 \: km} \: \: \: }} \\ \end{gathered} \end{gathered}`

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`{\underline{\huge \mathbb{S} {\large \mathrm {OLUTION : }}}} \\`

`\underline{ \sf{ \pmb{Given} \: that,}}`

`\begin{gathered}\begin{gathered} \qquad \qquad \hookrightarrow \: \sf{Speed = \red{200 \: kph}} \\ \end{gathered} \end{gathered}`

`\begin{gathered}\begin{gathered} \qquad \qquad \hookrightarrow \: \sf{Time = \blue{11 \: hours}} \\ \end{gathered} \end{gathered}`

`\sf{To \: \pmb{ find:}}`

• What is the distance?

`\sf{We \: know,}`

`\begin{gathered}\begin{gathered} \qquad \hookrightarrow \: \boxed{ \bold{ \: \: \green{ Distance} = \red{Speed} * \blue{ Time }\: \: }} \\ \end{gathered} \end{gathered}`

Therefore, by substituting the given values in the above formula:

`\begin{gathered}\begin{gathered}\sf\implies{ \green{Distance} = \red{Speed} * \blue{Time}} \\ \end{gathered}\end{gathered}`

`\begin{gathered}\begin{gathered}\sf\implies{ \green{Distance} = \red{200} * \blue{11}} \\ \end{gathered} \end{gathered}`

`\begin{gathered}\begin{gathered}\sf\implies{ \green{Distance} = \underline{\bold{ \green{ \: \: \: 2200 \: \: \: }}}}\\ \end{gathered} \end{gathered}`

`{ \blue{ \overline{ \qquad \qquad \qquad \qquad \qquad \qquad}}}`

`\large \sf{Thus,}`

`\begin{gathered}\begin{gathered} \qquad\sf\hookrightarrow \: {\underline{\bold{\green{Distance}}} \: = \: \boxed{\bold{ \green{ \pmb{ \: \: \: 2200 \: km\: \: \: }}}}}\\ \end{gathered} \end{gathered}`

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