The graph contains a parabola that opens down and has a vertex at (0, 4).
The graph contains a line that has a slope of 1 and a y-intercept of 2.
The solutions are the x-coordinates of any intersection points.
Answer:
A quadratic graph whose equation is....
x2 + x - 2
Explanation:
Firstly create your equation by moving all variables to one side....x2 + x + 2 - 4.
Then after drawing the graph...the solutions to the equation are the points at which the graph intercepts with the x-axis of the cartesian plane
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