151k views
3 votes
Solve for k such that a line passing through (-k, -5) and (-3, k+2) has a slope of 3/4. Show all work!

User Okovko
by
5.2k points

2 Answers

3 votes

Answer:

all work is shown and pictured and all complete

Solve for k such that a line passing through (-k, -5) and (-3, k+2) has a slope of-example-1
User Boileau
by
4.6k points
3 votes

Answer:

k = - 37

Explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- k, - 5) and (x₂, y₂ ) = (- 3, k+2)

m =
(k+2+5)/(-3+k), that is


(k+7)/(-3+k) =
(3)/(4) ( cross- multiply )

4(k + 7) = 3(- 3 + k) ← distribute both parenthesis

4k + 28 = - 9 + 3k ( subtract 3k from both sides )

k + 28 = - 9 ( subtract 28 from both sides )

k = - 37

User Sean Haddy
by
5.2k points