Question

Please help me with these!!!

Answer 1

Explanation:

The formula for midpoint is

`((x_1+x_2)/(2) ,(y_1+y_2)/(2) )`

where (x₁,y₁) and (x₂,y₂) are coordinates of end points and (x₁+x₂ /2 , (y₁+y₂ / 2) is the midpoint of the segment

9.

A(x₁y₁)

midpoint (3,4)

B(9,8)

Apply the formula

(x₁+3)/2 =9

x₁+3=18

x₁=18-3=15

and

(y₁+4)/2=8

y₁+4=16

y₁=16-4=12

(x₁,y₁)=(15,12)

10.

Mid-point =v (-3,-2)

End-point=w (3,5)

Other End-point=u (x₁,y₁) =?

Apply the formula

(x₁+3)/2=-3

x₁+3=-6

x₁=-6+3=-3

and

y₁+5=-2

y₁=-2-5=-7

(x₁,y₁)=(-3,-7)

11.

Finding mid-point of AB

A (2,4) and B (1,-3)

Apply formula

Mid-point of AB is ((x₁+x₂)/2 , (y₁+y₂)/2)

=((2+1)/2,(4+-3)/2)

=(3/2,1/2)= (1.5,0.5)

Mid-point of AB is (1.5,0.5)

12.

A (3.1, -2.1) and B (-0.52,-0.6)

finding mid-point, apply the formula

((x₁+x₂/2),(y₁+y₂ /2)

=((3.1+-0.52)/2,(-2.1+-0.6)/2)

=(2.58/2 , -2.7/2)

mid-point of AB (1.29,-1.35)

1.

End point 1 (-1,-1)

End point 2 (-5,-5)

Midpoint = ?

Apply

((x₁+x₂/2),(y₁+y₂/2) )

((-1+-5)/2,(-1+-5)/2)

((-6)/2,-(-6)/2)

midpoint x,y=(-3,-3)

2.

Endpoint 1 (-5,5)

End point 2 (2,-5)

Midpoint =?

Apply formula

((x₁+x₂/2),(y₁+y₂/2))

((-5+2)/2,(5+-5)/2))

((-3)/2,(0)/2)

midpoint (x,y)=(-1.5,0)

3.

Endpoint 1 (-4,2)

Endpoint 2 (2,2)

Midpoint= ?

Apply formula

((x₁+x₂ / 2), (y₁+y₂ /2) )

( ( -4+2 )/2 , (2+2)/2)

( (-2)/2 , (4)/2)

midpoint x,y = ( -1 , 2 )

4.

Endpoint 1(5,3)

Endpoint 2(-4,-1)

midpoint =?

Apply formula

((x₁+x₂ /2), (y₁+y₂ /2)

((5+-4 /2) , (3+-1)/2)

((1/2), (2/2))

midpoint x,y =(0.5,1)

5

points (-4,4) and (5,-1)

Apply the formula

((x₁+x₂ / 2), (y₁+y₂)/2)

((-4+5) /2 ), (4+-1)/2)

( 1/2, 3/2)

midpoint of line segment is ( 0.5, 1.5)

6

points (-5.1, -2) and (1.4, 1.7)

Apply formula

((x₁+x₂/2),(y₁+y₂ /2) )

((-5.1+1.4)/2,(-2+1.7))

((-3.7/2 , -0.3/2)

midpoint of segment is (-1.85,-0.15)

7.

Endpoint 1 (2,5)

Midpoint of segment (5,1)

Endpoint 2=(x₂,y₂)

Apply formula

((x₁+x₂ /2) ,(y₁+y₂ /2) )

(2+x₂)/2=5

2+x₂=10

x₂=10-2=8

(5+y₂)/2 =1

5+y₂=2

y₂=2-5=-3

Endpoint coordinates (x₂,y₂)= (8,-3)

8.

Endpoint 1 (-6,4)

Midpoint of segment (4,8)

Endpoint 2 (x₂,y₂)=?

Apply Formula

((x₁+x₂ )/2 , (y₁+y₂ /2) )

((-6+x₂)/2 ,(4+y₂)/2)

(-6+x₂)/2=4

-6+x₂=8

x₂=8+6=14

and

(4+y₂)/2=8

4+y₂=16

y₂=16-4

y₂=12

coordinates of endpoint are (14,12)