Answer:
Here is code in c++.
#include <bits/stdc++.h>
using namespace std;
int main()
{
// integer array to store 3 int value
int arr[3];
// double array to store 3 double value
double arr1[3];
double sum=0;
double avg;
double product=1;
double min=INT_MAX;
double max=INT_MIN;
cout<<"Enter 3 integer values:";
//read 3 integer values
for(int i=0;i<3;i++)
{
cin>>arr[i];
// find total sum
sum=sum+arr[i];
// calculate product
product=product*arr[i];
// finding minimum value
if(double(arr[i])<min)
min=double(arr[i]);
// finding maximum value
if(double(arr[i])>max)
max=double(arr[i]);
}
cout<<"Enter 3 double values:";
//read 3 double values
for(int i=0;i<3;i++)
{
cin>>arr1[i];
// find total sum
sum=sum+arr1[i];
// calculate product
product=product*arr1[i];
// finding minimum value
if(arr1[i]<min)
min=arr1[i];
// finding maximum value
if(arr1[i]>max)
max=arr1[i];
}
//calculate average of all 6 numbers
avg=sum/6;
// print the result
cout<<"sum of all: "<<sum<<endl;
cout<<"average of all: "<<avg<<endl;
cout<<"Product of all: "<<product<<endl;
cout<<"minimum of all: "<<min<<endl;
cout<<"maximum of all: "<<max<<endl;
return 0;
}
Step-by-step explanation:
Create two array "arr1" of int type to store 3 integer values and "arr2" of double type to store 3 double values.Calculate sum of all 6 numbers and find their average. After that calculate product of all the numbers.then find the minimum and maximum of all the values(in both integer and double).
Output:
Enter 3 integer values:5 2 10
Enter 3 double values:3.3 10.3 5.5
sum of all: 36.1
average of all: 6.01667
Product of all: 18694.5
minimum of all: 2
maximum of all: 10.3