Answer:
122.5 kW
Step-by-step explanation:
m = mass of the loaded elevator = 2.50 x 10³ kg = 2500 kg
t = time taken to raise the elevator = 10.0 s
h = height gained by the elevator = 50.0 m
g = acceleration due to gravity = 9.8 m/s²
Power spent is given as
P =
![(mgh)/(t)](https://img.qammunity.org/2020/formulas/engineering/college/3074tbajap1dt4lmve4w0qxgpxpzxq9k7p.png)
Inserting the values
P =
![((2500) (9.8) (50.0))/(10.0)](https://img.qammunity.org/2020/formulas/physics/college/fm964bf88jkpjinazvo1sx3ev2izv2p15h.png)
P = 122500 Watt
P = 122.5 kW (Since 1 kW = 1000 W)