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Output a table that show the cube of the numbers 1-15
(C++)

1 Answer

3 votes

Answer:

The c++ program to display cube of numbers from 1 to 15 is given below.

#include <iostream>

using namespace std;

int main() {

// variables declared and initialized

int num = 15, k, cube;

cout << " Cubes of numbers from 1 to 15 are shown below " << endl;

for( k = 1; k <= num; k++ )

{

// cube is calculated for each value of k and displayed

cube = k * k * k ;

cout << " \t " << cube << endl;

}

return 0;

}

OUTPUT

Cubes of numbers from 1 to 15 are shown below

1

8

27

64

125

216

343

512

729

1000

1331

1728

2197

2744

3375

Step-by-step explanation:

The variables are declared and initialized for loop, cube and for condition in the loop – k, cube, num respectively.

Inside for loop which executes over k, beginning from 1 to 15, cube of each value of k is calculated and displayed. The loop executes 15 times. Hence, cube for numbers from 1 to 15 is displayed after it is calculated.

for( k = 1; k <= num; k++ )

{

cube = k * k * k ;

cout << " \t " << cube << endl;

}

In the first execution of the loop, k is initialized to 1 and variable cube contains cube of 1. Hence, 1 is displayed on the screen.

In the second execution, k is incremented by 1 and holds the value 2. The variable cube contains cube of 2, which is calculated, and 8 gets displayed on the screen.

After each execution of the loop, value of k is incremented.

After 15 executions, value of k is incremented by 1 and k holds the value 16. This new value is greater than num. Hence, the loop terminates.

User Rgdigi
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