Question

Calculate the momentum of a photon of light that has a frequency of 5.09 x 10^14 HZ.

Answer 1

Momentum of a photon,
`P=1.13* 10^(-27)\ kg-m/s`

Step-by-step explanation:

It is given that,

The frequency of light,
`f=5.09* 10^(14)\ Hz`

We need to find the momentum of a photon. The relation between momentum and wavelength is given by :

`P=(h)/(\lambda)`

Since,
`\lambda=(c)/(f)`

`P=(fh)/(c)`, c is the speed of light

`P=(5.09* 10^(14)* 6.67* 10^(-34))/(3* 10^8)`

`P=1.13* 10^(-27)\ kg-m/s`

So, the momentum of a photon is
`1.13* 10^(-27)\ kg-m/s`. Hence, this is the required solution.