Question

When a voltage difference is applied to a piece of metal wire, a 10.0 mA current flows through it. If this metal wire is now replaced with a silver wire having twice the diameter of the original wire, how much current will flow through the silver wire?

Answer 1

10 mA

Step-by-step explanation:

We have given when a potential difference is applied then a current of 10 mA is flows so current i = 10 mA

According to ohms law voltage V =i R

And resistance is given as
`R= (\rho l)/(A)`

From the relation it is clear that resistance is inversely proportional to the area

As in new case the wire have twice diameter means 4 times the area so the resistance will decrease by 4 times from the previous resistance

As current
`i=(V)/(R)` current is inversely proportional to resistance so current will become 4 times of previous value

So current = 10×4=40 mA