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Given: DR tangent to Circle O.
If m _ RDC = 120°, then m DAC =
•60
•120
•240

Given: DR tangent to Circle O. If m _ RDC = 120°, then m DAC = •60 •120 •240-example-1
User Frops
by
4.8k points

2 Answers

1 vote

Answer:

Option C.

Explanation:

If a tangent and arc intersect at a point on a circle the measure of angle formed by the intersection will be half of the arc intercepted.

Therefore, m∠RDC =
(1)/(2)(mDAC)

Since m∠RDC = 120°

120 =
(1)/(2)(mDAC)

m(arcDAC) = 2×120°

m(arcDAC) = 240°

Option C. 240° is the answer.

User Karadayi
by
4.7k points
1 vote

Answer:

The measure of the arc DAC is 240°

Explanation:

we know that

The semi-inscribed angle is half that of the arc it comprises.

so

m∠RDC=(1/2)[arc DAC]

we have

m∠RDC=120°

substitute

120°=(1/2)[arc DAC]

240°=[arc DAC]

Rewrite

arc DAC=240°

User Ryan Williams
by
4.8k points