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N^2-4n
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User Nbpeth
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1 Answer

7 votes

Answer:

Two solutions are found:

n=0 , n= 4 ....

Explanation:

n^2-4n = 0

Take common from the given expression:

n(n-4)=0

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately;

n(n-4)=0

n = 0.

n-4 = 0.

Add 4 at both sides:

n-4+4 = 0+4

n = 4

Therefore two solutions are found:

n=0 , n= 4 ....

User Shlublu
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5.8k points