Question

Through (2,0) slope = -5/3 write the slope intercept of the equation

Answer 1

`y=-(5)/(3)x+(10)/(3)`

Explanation:

The equation of a line has the following form:

`y=mx+b`

Where m is the slope of the line and b is the intercept with the y axis.

In this case we know that:

`m=-(5)/(3)`

So the equation is:

`y=-(5)/(3)x+b`

To find b we substitute the point in the equation and solve for b

`0=-(5)/(3)(2)+b`

`b=(10)/(3)`

Then the equation of the line in the form of pending interception is:

`y=-(5)/(3)x+(10)/(3)`

Answer 2

For this case we have that the equation of a line of the slope-intersection form is given by:

`y = mx + b`

Where:

m: It's the slope

b: It is the cut-off point with the y axis

In this case we have the following data:

`m = - \frac {5} {3}\\(x, y) :( 2,0)`

Then, the equation is of the form:

`y = - \frac {5} {3} x + b`

We find "b" replacing the point:

`0 = - \frac {5} {3} (2) + b\\0 = - \frac {10} {3}\\b = \frac {10} {3}`

Thus, the equation is:

`y = - \frac {5} {3} x + \frac {10} {3}`

Answer:

`y = - \frac {5} {3} x + \frac {10} {3}`