Answer:
The exit temperature of hot water =200.005°F
Step-by-step explanation:
Given that
Volume flow rate of water = 20 gpm ⇒
Volume flow rate of water =
inlet temperature of water = 200°F
Heating load = 92.000 Btu/hr ⇒ Heating load= 0.0269 KW
We know that mass flow rate is given as

So mass flow rate of water = 1000 x 0.00126 Kg/s
mass flow rate of water= 1.26 Kg/s
Now by balancing heat
Heating load =


=200.005°F
So the exit temperature of hot water =200.005°F