Question

Find the percent change in cutting speed required to give an 80% reduction in tool life when the value of n is 0.12.

Answer 1

Answer:21.3%

Step-by-step explanation:

Given

80 % reduction in tool life

According to Taylor's tool life

`VT^n`=c

where V is cutting velocity

T=tool life of tool

80 % tool life reduction i.e. New tool Life is 0.2T

Thus

`VT^(0.12)=V'\left ( 0.2T\right )^(0.12)`

`V'=(V)/(0.2^(0.12))`

`V'=(V)/(0.824)`=1.213V

Thus a change of 21.3 %(increment) is required to reduce tool life by 80%