Question

Consider an adiabatic throttling valve with water entering at pressure of 1.5 MPa, a temperature of 150°C and a velocity of 4.5 m/s. Determine the velocity at the exit.

Answer 1

So the exit velocity of water is 4.5 m/s

Step-by-step explanation:

Given that

Water entering pressure = 1.5 MPa

Temperature = 150°C

Velocity = 4.5 m/s

From first law of thermodynamics for open system

`h_1+(V_1^2)/(2)+Q=h_2+(V_2^2)/(2)+W`

Here given that valve is adiabatic so Q= 0

In valve W= 0

Wen also also know that throttling process is an constant enthaply process so

`h_1=h_2`

`h_1+(V_1^2)/(2)+Q=h_2+(V_2^2)/(2)+W`

`h_1+(V_1^2)/(2)+0=h_1+(V_2^2)/(2)+0`

So from above equation we can say that

`V_2=V_1`

So the exit velocity of water is 4.5 m/s