Question

A wire is formed into a circle having a diameter of 11.1 cm and is placed in a uniform magnetic field of 2.79 mT. The wire carries a current of 5.00 A. Find the maximum torque on the wire.

Answer 1

Maximum torque on the wire is
`1.34* 10^(-4)\ N-m`

Step-by-step explanation:

It is given that,

Diameter of the wire, d = 11.1 cm = 0.111 m

Radius of wire, r = 0.0555 m

Magnetic field,
`B=2.79\ mT=0.00279\ T`

Current, I = 5 A

We need to find the maximum torque on the wire. Torque is given by :

`\tau=IAB\ sin\theta`

Torque is maximum when,
`\theta=90`

`\tau=IAB`

`\tau=5* \pi * (0.0555)^2* 0.00279`

`\tau=0.000134\ N-m`

or

`\tau=1.34* 10^(-4)\ N-m`

So, the maximum toque on the wire is
`1.34* 10^(-4)\ N-m`. Hence, this is the required solution.