Question

A sample of sodium-22 (Z= 11) decays to neon-22 (Z 10). The alf-life of this sodium isotope is 2.5 years. The masses of the sodium-22 and neon- 22 atoms are 21.994434 u and 21.991383 u, respectively. The initial mass of the sodium-22 sample is 5 mg. [2 points] What is the radius of the sodium-22 nucleus?

Answer 1

`3.5022* 10^(-15) m`is the radius of the sodium-22 nucleus.

Step-by-step explanation:

`r=r_o* A^{(1)/(3)}`

Where:

`r_o=1.25 * 10^(-15) m` = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons or atomic mass

Radius of the sodium-22 nucleus

Atomic mass of Na-22= 21.994434 u

A = 21.994434

`r=1.25* 10^(-15) m* (21.994434)^{(1)/(3)}`

`r=3.5022* 10^(-15) m`

`3.5022* 10^(-15) m`is the radius of the sodium-22 nucleus.