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A typical gamma ray emitted from a nucleus during radioactive decay may have an energy of 320keV. What is its wavelength in angstroms? A) 0.39 ANGSTROMS

B) 0.039 ANGSTROMS
C) 320 ANGSTROMS
D) 390 ANGSTROMS
E) 0.093 ANGSTROMS

User AL The X
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1 Answer

4 votes

Answer:

The wavelength is 0.39 angstroms.

(A) is correct option.

Step-by-step explanation:

Given that,

Gamma ray emitted from a nucleus during radioactive decay may have an energy = 320 keV

We need to calculate the wavelength

Using formula of energy


E=(hc)/(\lambda)


\lambda=(hc)/(E)

Where, E = energy

h = plank's constant

c = speed of light

Put the value into the formula


\lambda=(6.6*10^(-34)*3*10^(8))/(320*1.6*10^(-19))


\lambda=0.39\ \AA

Hence, The wavelength is 0.39 angstroms.

User Remko Duursma
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