Question

Find the net charge of a system consisting of 206 electrons and 161 protons. Express your answer using two significant figures.

Answer 1

-72\times 10^{-19}C[/tex]

Step-by-step explanation:

Both electron and proton have the same amount of charge but signs are opposite , electron contains negative charge and proton contain positive charge

Charge on 1 electron =
`-1.6* 10^(-19)C`

So charge on 206 electron
`=-206* 1.6* 10^(-19)C`

Charge on 1 proton =
`-1.6* 10^(-19)C`

So charge on 161 electron
`=-106* 1.6* 10^(-19)C`

So charge of the system =
`(-206+161)* 1.6* 10^(-19)C`

`=-72* 10^(-19)C`