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Supposef:ZZ is defined by f(x) = 2x^2 + 1. a. Explain using the definition of onto functions why the function f is or is not an onto function b. Explain using the definition of one-to-one functions why the function f is or is not a 1-1 function

User Mavi
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a. Since
f:\Bbb Z\to\Bbb z, the function
f(x)=2x^2+1 is not onto because not every element in the codomain
\Bbb Z is represented by
f(x). For any
x\in Z, we have
x^2\ge0, so
x^2+1\ge1, which means there is no choice of
x such that
f(x)\le0.

b.
f is not one-to-one because there are infinitely many choices of
x for which
f(-x)=f(x). For example,
f(1)=1^2+1=2 and
f(-1)=(-1)^2+1=2.

User Cwoebker
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