Question

When 224-nm light falls on a metal, the current through a photoelectric circuit is brought to zero at a stopping voltage of 1.84 V. What is the work function of the metal?

Answer 1

3.71 eV

Step-by-step explanation:

λ = Wavelength of light = 224 nm = 224 x 10⁻⁹ m

c = speed of electromagnetic wave = 3 x 10⁸ m/s

V₀ = stopping potential = 1.84 volts

W₀ = Work function of the metal = ?

Using the equation

`(hc)/(\lambda ) = eV_(o) + W_(o)`

`((6.63* 10^(-34))(3* 10^(8)))/(224* 10^(-9) ) = (1.6* 10^(-19))(1.84) + W_(o)`

`W_(o)` = 5.94 x 10⁻¹⁹

`W_(o)` = 3.71 eV