Answer:
The contents in ax and bx registers are as following:-
ax=3432
bx=4670
Step-by-step explanation:
mov command in 8086 is an important command in 8086 microprocessors.It moves the data from the source to destination.
mov destination,source
add it adds the data to the destination with the content of destination.
add a,b means add b to a.
in operation mov ax,3432 we are moving 3432 to ax register similarly moving 1238 to bx.
Now adding ax to bx so the content of bx =1238+3432 that is 4670.