Question

A sample of cast iron with .35 wt%C is slow cooled from 1500C to room temperature. What is the fraction of proeutectoid Cementite phase in this material?

Answer 1

So the fraction of proeutectoid cementite is 44.3%

Step-by-step explanation:

Given that

cast iron with 0.35 % wtC and we have to find out fraction of proeutectoid cementite phase when cooled from 1500 C to room temperature.

We know that

Fraction of proeutectoid cementite phase gievn as

`{w_p}'=\frac{{C_o}'-0.022}{0.74}`

Now by putting the values

`{w_p}'=(0.35-0.022)/(0.74)`

`{w_p}'=0.443`

So the fraction of proeutectoid cementite is 44.3%