Question

10Ω resistor and a 5 Ω are connected in parallel. This pair is then connected in series in with another 4 Ω resistor. What is the equivalent resistance of the circuit?

Answer 1

7.33 Ω

Step-by-step explanation:

10Ω resistor and a 5 Ω are connected in parallel

so,

R₁=(10X5)/(10+5)

=(50/15) Ω

=3.33 Ω

This pair is then connected in series in with another 4 Ω resistor

R₂=R₁+4

=(3.33+4) Ω

=7.33 Ω